(from Division of Labor)
With splitting the pot on ties, the only Nash equilibrium is for everyone to send in 0. Any other result is unstable, as everyone has incentive to move to the 2/3 point, which will tend to decrease the average towards 0. And once it is there, no one profits by moving. It also matters whether the metric is "closest to 2/3", or "closest to 2/3 from above". With the latter metric, all 0 is not stable, because if one person moves to 1, they win. It is unclear to me what the answer is in this case, its certainly much harder.
Another interesting point is that this game is ripe for collusion. Suppose everyone knows to pick 0. If my partners and I have a rough idea of how many people there are, some of us pick 100, and one of us picks the 2/3 point.
My good friend, Neil Emerick in South Africa who runs Global Economic Software, sent me the following question. I pass it along to you here. If you'd like to add to his database of answers, e-mail him at
neilemerick[at]wol[dot]co[dot]za.
Imagine a company is running a competition for a prize of 10,000 dollars.
They challenge people to send in a number between 1 and 100. The prize will
go to the person(s) who picked the number that was 2/3rds of the average
number sent in.
What number would you send in?
With splitting the pot on ties, the only Nash equilibrium is for everyone to send in 0. Any other result is unstable, as everyone has incentive to move to the 2/3 point, which will tend to decrease the average towards 0. And once it is there, no one profits by moving. It also matters whether the metric is "closest to 2/3", or "closest to 2/3 from above". With the latter metric, all 0 is not stable, because if one person moves to 1, they win. It is unclear to me what the answer is in this case, its certainly much harder.
Another interesting point is that this game is ripe for collusion. Suppose everyone knows to pick 0. If my partners and I have a rough idea of how many people there are, some of us pick 100, and one of us picks the 2/3 point.


Comments
I agree that the only NE is for everyone to pick 1. (modulo some modifications of the game that you keep making in the comments)
To which I say, SO WHAT?
Nash Equilibrium carries zero predictive value in one-shot games.
A bunch of people are going to send in 66, and a bunch more people are going to send in 22, and a bunch more people are going to ...
In a game like this, unless you're playing with only game theorists (and maybe even then), picking as low as possible is a sure way to lose.
If I were playing (and I consider myself a game theorist), I'd put in a guess in the 20s.
But don't take my word for it. I'll do a poll.
split the winning among us.
It's an interesting problem though. You can't apply math to psychology very effectively. It reminds me of a game I was showing
It's easy to beat random, and it's easy to beat any strategy that you know, but it's hard to figure out what portion of people will go meta to what extent :)